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Online o.mag
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« Reply #20 on: July 11, 2011, 12:38:21 pm »
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hi deep max

i find a photo in the old forum "

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i thing all transitor is in a wrong position

olivier

Posted on: July 11, 2011, 11:53:30 AM


you must see the datasheet of original part and you new part

Posted on: July 11, 2011, 12:17:14 PM
j' answered too quickly the bc547 and 557 are in the opposite direction from the 2N4124 AND 26
afflicted

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Offline deep maxTopic starter
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« Reply #21 on: July 11, 2011, 02:37:34 pm »
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I think I have them set correctly look at the picture on the front page

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« Reply #22 on: July 11, 2011, 03:02:07 pm »
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OK : my photo is with original transistor part
PS : for replace MPSA14 the BC517 work
i use it

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« Reply #23 on: July 14, 2011, 06:53:01 pm »
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hi all

while excavating on the forum j' found a confirmation of the tensions

olivier


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« Reply #24 on: July 15, 2011, 09:31:23 am »
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Hi o.mag
             any op need to run a negative voltage (Vss=--) and positive voltage(Vdd=++)



toute op besoin d'exécuter une tension négative (Vss =--) et une tension positive (Vdd = + +)

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« Reply #25 on: July 15, 2011, 12:53:08 pm »
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hi japanese
 For qu' a AOP functions (into linear) it n' necessarily d' need does not have; a symmetrical food. It is necessary that the tension differential between its entered either null. one can thus perfectly do it with a strictly positive food but by polarizing the entries semi-tension with a dividing bridge has (c' is a virtual mass). In l' example which you chose the virtual mass m' is not has semi-tension but almost has 12v Like l' AOP is assembled out of reverser only the negative part of the signal d' entry will be amplified. (the signal d' entry is centered on the +12V)

cordially

bonjour
Pour qu'un AOP fonctionne (en linéaire ) il n'a pas nécessairement besoin d'une alimentation symétrique.Il faut que la tension différentiel entre ses entré soit nulle. on peut donc parfaitement le faire avec une alimentation strictement positive mais en polarisant les entrées a mi-tension avec un pont diviseur (c'est une masse virtuelle).
Dans l'exemple que tu as choisi la masse virtuelle m'est pas a mi-tension mais presque a 12v
Comme l'AOP est monté en inverseur seul la partie négative du signal d'entrée sera amplifié.(le signal d'entrée est centré sur le +12V)

cordialement
 olivier

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« Reply #26 on: July 15, 2011, 01:46:09 pm »
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Just to help out, replace the word "food" with "power supply" in o.mag's last post

Regards Xavier

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« Last Edit: July 15, 2011, 01:48:47 pm by xavier »
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So many questions so little time

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« Reply #27 on: July 15, 2011, 01:54:30 pm »
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Hi o.mag

            I hope you note -- = - 1.25V  and the application to the db 2010

            J'espère que vous noter --=-1.25v  et de l'application sur le db 2010

         

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« Reply #28 on: July 15, 2011, 02:07:27 pm »
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if you built the dbp2010 measurement -- compared to the mass: c' is +1,25V
(for "food" it babel fish)

si tu a construit le dbp2010 mesure -- par rapport a  le masse  : c'est +1,25V

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« Reply #29 on: July 15, 2011, 03:22:45 pm »
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Hi o.mag    mon ami
                             Question de logique

best time

j.   

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