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Offline Cornelius
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« Reply #170 on: January 26, 2010, 02:40:02 pm »
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Aliman  . Dont confuse yourself . There was no short in the circuit when it was sent to you . It worked properly . Where do you have to look ? Well , I would say in the area's you worked on after you received the detector .  Make sure that your IC's are in order . To start I would replace the  TIP 13 A     and the IC 5  , the 741    . You got to try a few things  . Cornelius

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« Reply #171 on: January 26, 2010, 02:57:04 pm »
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Remember that a strand of wire could have come of when you cut it like for the ground or one of the power wires it does not have to be big to create a lot of S@#T and it always seems to get stuck in the most awkward places that is why I told you to use a brush I had one that took me more than a day to find.  Angry

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Offline Peti80
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« Reply #172 on: January 26, 2010, 03:13:34 pm »
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Ali, first note or take a photo for yourself on how IC4 and IC5 is seated in the PCB, to have it for later reference. As i saw those IC's have a socket, so it's easy to remove them. If so, remove them. Put back the output of the 7905 into the PCB. Switch on. Measure regulator output voltage. If one of the IC's were dead -shorting out the negative rail- now you should have the correct voltage. Can you check that voltage with IC4 and IC5 removed?

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Offline alimanTopic starter
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« Reply #173 on: January 26, 2010, 03:33:12 pm »
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 OK, but IC4 is soldered to the PCB (round can type ) , IC5 is in a socket.
 I'll first try it with out IC5 and measure the Output of 79L05. If it's not -5v I'll remove IC4 and try it again.
Aliman

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« Reply #174 on: January 26, 2010, 03:50:42 pm »
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YOU are wasting your time (that?s my opinion) I hope that you will replace the IC?s the right way round. I will have no further part in this process of self destruction

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« Reply #175 on: January 26, 2010, 03:58:59 pm »
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Hey Xavier, this is no self destruction. Ali says there are no signs of traces shorting, and the fact that the 7905 output voltage is not dropped down to zero, it's not very likely that there is a hard short. It's only pulled down to 3.4V, so it must be some semiconductor failure, not a direct metallic short. At least this is what the story suggests.

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« Reply #176 on: January 26, 2010, 04:08:07 pm »
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If he did like I told him he would have seen that the transistor next to the 7905 has rust on all three pins THAT should be removed cleaned and replaced

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« Reply #177 on: January 26, 2010, 04:28:42 pm »
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 I removed IC5 and checked the Output on 79L05 and it up by 0.25V. So I don't think its IC5 causing the problem.
Xavier are you  talking about TR4, good eye. I'll have to check those pins Thanks. If this dosen't work, I'll remove IC4 and check the output again.

Sorry to everybody for causing a headache, with my Self created problem.
Thousand Pardons

P.S. If nothing else, I've learned that, I new far less about electronics then I thought.
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« Reply #178 on: January 26, 2010, 04:41:37 pm »
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Aliman It was working that we know you did not pop the regulators that we also know if there is a heavy load on the regulators they cut out that we know to IF you think about it there is very little chance that you could have popped any of the components there for it has to be something that you did with your very poor soldering (I don't blame you for it) so look at all that you did go as far as undoing what you did one at a time testing all the time as you go along I can only tell you what you should do I cant do it for you I'm on the other side of the world and you will have to have a lot of patience as these are the most type of problems well one of the worst the worst is intermittent problems

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« Reply #179 on: January 26, 2010, 05:41:04 pm »
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Ali , you asked me to send you a PCB . I did send you a complete  working detector . Now we are in trouble .  May I give you a last suggestion .   Remove all transistors .  Get an 8 dill socket for the  IC 709  and get the newer version of the 709 that will fit the  socket  .  Renew all IC'S  . Only use  9V batteries . Leave the capacitors and the resistors .  Renew the diodes . This will give you a good result . Cornelius

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